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- Re: Query
Query
17-10-2015 3:30 PM
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In the context of a landline phone line, does anyone here know what "Earth A" means?
TIA
TIA
Message 1 of 6
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Re: Query
17-10-2015 4:36 PM
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If you think of the telephone circuit coming from the exchange the positive (+) is called the B leg and the negative (-) is the A leg, so earth A means that the negative is in contact with earth somewhere on the line
HTH
HTH
Message 2 of 6
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Re: Query
17-10-2015 5:47 PM
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Thanks, 2u2me. So that sounds like a fault to me.
Message 3 of 6
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Re: Query
17-10-2015 6:07 PM
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Yep its a fault, electric`s lazy, it will always take the shortest path, so you will not be getting the full 50 volts
Message 4 of 6
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Re: Query
18-10-2015 5:07 PM
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For the record, under quiescent conditions the 'B' leg will normally be at -50V (negative leg), and the 'A' leg is earthed at the exchange (positive leg).
So, as 2u2me advises, 'Earth A' is a fault, and will be a greater or lesser problem depending on its location, and whether it's a full or resistive earth.
So, as 2u2me advises, 'Earth A' is a fault, and will be a greater or lesser problem depending on its location, and whether it's a full or resistive earth.
Murphy was an optimist
Zen FTTC 40/10 + Digital Voice FRITZ!Box 7530
BT technician (Retired)
Zen FTTC 40/10 + Digital Voice FRITZ!Box 7530
BT technician (Retired)
Message 5 of 6
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Re: Query
18-10-2015 6:39 PM
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As engineers we always spoke of EARTH A, BATTERY B.,exchanges work +ve earth so effectively the A leg is earth thus the B(battery) leg is -50v with respect to earth.Testing towards an exchange will show earth on the A leg.
sorry for any confusion.
sorry for any confusion.
Message 6 of 6
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