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## Maths Question

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##### Maths Question

##### Maths Question

01-08-2013 6:53 PM

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A (4)

B(4)

C(6)

D(2)

E(6)

F(6)

G(4)

H(4)

Working down the list we can have A1, B1, C1, D1, E1, F1, G1, H1, then we change H to 2, then 3, then 4, then we change G to 2 and H to 1, then H2 etc.. until we eventually wind up with 44626644. I can't quite figure out how many different possible combinations there are, 8^36 gives a silly number, there is probably a really easy solution that I'm not quite getting, so any hints tips or even the solution?

6 REPLIES

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##### Re: Maths Question

##### Re: Maths Question

01-08-2013 7:00 PM

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Isn't it 4*4*6*2*6*6*4*4?

= 110592

= 110592

##
##### Re: Maths Question

##### Re: Maths Question

01-08-2013 7:19 PM

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##### Re: Maths Question

##### Re: Maths Question

01-08-2013 8:16 PM

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Multiplying the numbers will give you the correct value of possible outcomes.

That's RPM to you!!

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##### Re: Maths Question

##### Re: Maths Question

01-08-2013 8:22 PM

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So it really is 110k different combinations? That's way more than anticipated, thanks you two

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##### Re: Maths Question

##### Re: Maths Question

01-08-2013 8:40 PM

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That's RPM to you!!

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##### Re: Maths Question

##### Re: Maths Question

01-08-2013 9:06 PM

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