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Figure this out.

Community Veteran
Posts: 7,928
Thanks: 603
Fixes: 8
Registered: 02-08-2007

Figure this out.

Is it possible to speak at normal speed for one minute, without repeating the same word twice but using words that must not contain the letter "A" ?
Answer tomorrow unless one of you bright folks comes up with the answer before then ! Smiley
6 REPLIES
alanf
Aspiring Pro
Posts: 1,931
Thanks: 77
Fixes: 1
Registered: 17-10-2007

Re: Figure this out.

Someone reading words (not definitions) from a dictionary of a language not based on the Roman alphabet? Greek? Japanese?
JamesM
Grafter
Posts: 1,103
Registered: 24-06-2009

Re: Figure this out.

Counting numbers ?
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,30,40,50,60,70,80,90,100,200,300,400,500 ect
James
Grafter
Posts: 21,036
Registered: 04-04-2007

Re: Figure this out.

I thought you had it for a moment there, but you'll be repeating words.
Twenty one, Twenty two, etc.
JamesM
Grafter
Posts: 1,103
Registered: 24-06-2009

Re: Figure this out.

I did too James, I skipped the repateated numbers though by going from 20 to 30 and from 100 to 200, but after 900 you get 1000 which has an a. It works though if you speak very slowly  Wink
Community Veteran
Posts: 7,928
Thanks: 603
Fixes: 8
Registered: 02-08-2007

Re: Figure this out.

That was quick !
the answer was the numbers.
Depends of course on agreeing that twentyone, twentytwo, twentythree, etc are all single words !
Certainly some bright folk at PN.  Wink
Community Veteran
Posts: 13,927
Thanks: 515
Fixes: 8
Registered: 01-08-2007

Re: Figure this out.

Quote from: James
I thought you had it for a moment there, but you'll be repeating words.
Twenty one, Twenty two, etc.

Ah but you're assuming the person is counting them as strings instead of integers  Cheesy  Grin
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