Another algebra question...

Mav · 06-04-2007

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VileReynard · 01-09-2007

42

Mav · 06-04-2007

No

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Browni · 02-03-2016

48

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PeterLoftus · 27-05-2011

21

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7up · 01-08-2007

19

Horse = 10

2 horse shoes = 4 and so therefore one show = 2

2 boots = -2 and so one boot = -1

Horse X 1 shoe = 10 X 2 = 20

+ -1 = 19

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198kHz · 30-07-2008

Assuming normal arithmetic procedure ie horse and horseshoe resolved first: Answer = 80

Otherwise possibly 48

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Mav · 06-04-2007

One person has so far got the right answer...

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Mook · 16-10-2014

Horse = 10

Horseshoe = 2

Boot = 1

Likewise on reflection it's 22 as I've just realised there is only one horseshoe in the last item.

198kHz · 30-07-2008

Oops.

On reflection - it's 21

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rogadodge · 08-10-2010

Just noticed only one horseshoe, therefore value of 2 not 4 so...

The bottom line is 2+10x2. Depending on ow you interpret the mathematical rules its either

(2+10) x 2 = 12 x 2 = 24 or

2+ (10x2) = 2+20 = 22.

VileReynard · 01-09-2007

Mook wrote:

Horse = 10

Horseshoe = 2

Boot = 1

Likewise on reflection it's 22 as I've just realised there is only one horseshoe in the last item.

horse = 10

horseshoe = 4

boot = 2 (because horseshoe - boot = 2)

So boot + horse x horseshoe = 42

rogadodge · 08-10-2010

just noticed again...only one boot.

therefore 1+10x2.

so either 21 or 22, again depending on interpretation of mathematical rules.

Strat · 14-04-2007

42 then looked closer and arrived at 21

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rogadodge · 08-10-2010