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Subnetting question


Subnetting question

Thanks to PN i have a block of addresses for my training purposes, thanks Cheesy

My question is i now have a mask ending 252 which is 11111000 in binary.
This means the last three digits are for the host; fine.
What i don't understand is how i have 4 addresses with only 3 availible for the host. (router, gateway, spare and broadcast) :shock:

Thanks for looking Cheesy

Subnetting question

Actually, 252 is 11111100 in binary

(you had 11111000 - that would be a mask to allow 8 addresses)

Remember that you have 4 addresses available, so they "end" 00, 01, 10, 11

I've never had a block of addresses, so remainder is from theory, not experience:

AFAIK, your router will take the first of the block, you can assign the next two to
PCs on your LAN, and the last is the "broadcast" address.
Posts: 1,090
Registered: 08-04-2007

Subnetting question

An IPv4 (128 bit) single octet address range is 256 digits long (0 to 255) so 256 - 252 = 4 addresses left. 00 is reserved for the network address and 11 for the broadcast address for your subnetwork. This leaves 2 host addresses 01 and 10.

When counting up in binary from you network address is as follows: 00, 01, 10, 11.

Hope this sheds some light on your question?

Subnetting question

yes, thanks for you help both Cheesy

Subnetting question

Ah... you're back..

So they let you out at weekends for "good behaviour" :lol:

Hope your testing goes well...

Subnetting question

yes, i am back. Thanks, i'll let you know Cheesy